Question 2.10: In the manufacture of vinyl chloride (VC) by the pyrolysis o...

Basis: 5000 kg/h VC (the required quantity).

Reaction: C_{2}H_{4}Cl_{2}\longrightarrow C_{2}H_{3}Cl+HCl
mol weights DCE 99, VC 62.5
kmol/h VC produced = \frac{5000}{62.5}=\underline{\underline{80} }
From the stoichiometric equation, 1 kmol DCE produces 1 kmol VC. Let X be DCE feed
kmol/h:
Per cent conversion = 55 = \frac{80}{X} \times 100
X= \frac{80}{0.55} =\underline{\underline{145.5 kmol/h} }
In this example the small loss of DCE to carbon and other products has been neglected.
All the DCE reacted has been assumed to be converted to VC.