In the single-bay, post-and-beam deck illustrated, planks typically are available in nominal widths of four or six inches, but for the purposes of analysis, it is permissible to assume a unit width equal to one foot. Determine the plank, beam, and column reactions.

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Load on the deck (live load, or [latex] LL[/latex]) =[latex] 60 \space psf [/latex]

Deck weight (dead load, or [latex]DL[/latex]) =[latex]8 \space psf[/latex]

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Total load ([latex]LL[/latex] + [latex]DL[/latex]) =[latex]68 \space psf[/latex]

PLANK REACTION Looking at the deck in elevation, the load [latex] \omega [/latex] is determined by multiplying the pounds per square foot load by the tributary width of the plank. Therefore:

[latex] \omega =68\# /ft.^{2} (1^\prime )=68\# /ft.[/latex]

BEAM REACTION The planks load the beams with a load of [latex]68\#[/latex] per foot of the plank span. Half of the plank load is transferred to each beam. The beams are loaded by the planks with a load of [latex]272 \#[/latex] per foot of the beam span.

[latex] R=\frac{\omega L}{2} =\frac{68\# /ft.^{2} (8^\prime )}{2} =272 \space \# [/latex] (Beam reaction)

In addition, the beam has a self-weight equivalent to [latex] 10 \# /ft.[/latex]

COLUMN REACTION Half of each beam load is transferred to the column at each corner of the deck. The columns are loaded by the beams with loads of [latex]1,692\#[/latex] at each column. Assume each column has a self-weight of [latex]100\#[/latex] .

[latex]R=\frac{\omega L}{2} =\frac{(272+10)\# /ft.(12^\prime )}{2}[/latex]

[latex]=1,692 \space \#[/latex] (Column reaction)

GROUND REACTION The load at each column is resisted by an equivalent ground reaction of [latex]1,792\#[/latex].

Question 4.1: In the single-bay, post-and-beam deck illustrated, planks ty...

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