Refer to Figure 19-17. Find V_{th} for the circuit within the beige box as viewed from terminals A and B.
Refer to Figure 19-17. Find V_{th} for the circuit within the beige box as viewed from terminals A and B.
First remove R_{L} and determine the voltage across the resulting open terminals, which is V_{th}Find V_{th} , by applying the voltage-divider formula to X_{C} and R
V_{th}= V_{R}= \left(\frac{R\angle 0°}{R – jX_{c}} \right)V_{s}= \left(\frac{10\angle 0°k\Omega }{10 \ k\Omega – j10 \ k\Omega } \right)5 \angle 0°V\ \ \ \ \ \ =\left(\frac{10\angle 0°K\Omega }{14.1\angle -45°K\Omega} \right)5\angle 0°V=3.55\angle 45°V
Notice X_{L} has no effect on the result, since the 5 V source appears across X_{C}and R in combination.