Show by direct calculation that det(AB) = det(A) det(B) for the matrices
A=\left[\begin{array}{ll}2 & 1 \\1 & 3\end{array}\right] \quad \text { and } \quad B=\left[\begin{array}{rr}-1 & 3 \\2 & -2\end{array}\right].
Show by direct calculation that det(AB) = det(A) det(B) for the matrices
A=\left[\begin{array}{ll}2 & 1 \\1 & 3\end{array}\right] \quad \text { and } \quad B=\left[\begin{array}{rr}-1 & 3 \\2 & -2\end{array}\right].