Question 3.31: Solve Problem 3.8 using Matlab^†††††. Also calculate % volta...

Solve Problem 3.8 using Matlab^{ \dagger \dagger \dagger \dagger \dagger } . Also calculate % voltage regulation and \eta at full load and 0.8 pf lagging.

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Steps for computing circuit model parameters, voltage regulation and Efficiency at full load for a Transformer using MATLAB.

Open-Circuit Test The equivalent circuit as seen on open-circuit test is given in Fig. 3.23(b).

Applied voltage =V_{1}  (rated) Current drawn = 10

Power input = I0

Y_{0}=\frac{I_{0}}{V_{1}}, G_{i}=\frac{P_{0}}{V_{1}^{2}}

 

B_{m}=\sqrt{Y_{0}^{2}-G_{i}^{2}}

Short-Circuit Test The equivalent circuit as seen during short-circuit test is drawn in Fig. 3.23(b).

Applied voltage =V_{sc} (a fraction of rated value)

Current drawn = I_{sc} (nearly full load value)

Power input = P_{sc} = P_{c} (copper loss)

Z=\frac{V_{sc}}{I_{sc}} , R=\frac{P_{sc}}{(I_{sc})^{2}}

 

X=\sqrt{Z^{2}-R^{2}}

Voltage Regulation

% voltage regulation =\frac{voltage  drop}{rated  secondary  voltage  at  full  load  and  specified  pf} \times 100

or,                                             VR=\frac{I(R \cos \phi \pm X \sin \phi )}{V_{2}} \times 100; + for lagging pf;

– for leading pf

where

I = secondary current

R = equivalent resistance referred to secondary

X = equivalent reactance referred to secondary

\phi = power factor angle

Efficiency at full load

Efficiency at full load = \frac{Full  load  output\times  100}{Full  load  output + Core  loss + Copper  loss  at  full  load} =\frac{P}{P+P_{i}+P_{c}} \times 100

MATLAB PROGRAM

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P=50000;

V1=2200;

V2=110;

V0=110;

I0=10;

P0=400;

Y0=I0./V0

Gi=P0./(V0^2)

Bm=sqrt (Y0^2-Gi^2)

Vsc=90;

Isc=20.5;

Psc=808;

Z=Vsc./Isc

R=Psc./Isc^2)

X=sqrt (Z^2-R^2)

TR=2200/110;

Gi_HV=Gi./(TR^2)

Bm_HV=Bm./(TR^2)

R_LV=R./(TR^2)

X _LV=X./(TR^2)

I2=P./V2

pf=0.8;

Th=acos(pf)

dV=I2.*(R_LV.*cos(Th)+X_LV.*sin(Th))

VR=(dV./V2)*100

Pi=P0

Pc=Psc

EFF_Full_load=(P*100)./(P+Pi+Pc)

y0 =

0.0909

Gi =

0.0331

Bm =

0.0847

Z =

4.3902

R =

1.9227

X =

3.9468

Gi_HV =

8.2645e-005

Bm_HV =

2.1171e-004

R_LV =

0.0048

X_LV =

0.0099

I2 =

454.5455

Th =

0.6435

dV =

4.4389

VR =

4.0354

Pi =

400

Pc =

808

EFF_Full_load =

97.6410

Note For manual solution, refer solved Problem 3.3 of the Authors’ book [76]

^{ \dagger \dagger \dagger \dagger \dagger } For detailed write-up on MATLAB, the reader is encouraged to read Appendix G of the authors’ book “Modern Power System Analysis”, 3rd ed. Tata McGraw-Hill, New Delhi, 2003.

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