Solve Problem 3.8 using Matlab^{ \dagger \dagger \dagger \dagger \dagger } . Also calculate % voltage regulation and \eta at full load and 0.8 pf lagging.
Solve Problem 3.8 using Matlab^{ \dagger \dagger \dagger \dagger \dagger } . Also calculate % voltage regulation and \eta at full load and 0.8 pf lagging.
Steps for computing circuit model parameters, voltage regulation and Efficiency at full load for a Transformer using MATLAB.
Open-Circuit Test The equivalent circuit as seen on open-circuit test is given in Fig. 3.23(b).
Applied voltage =V_{1} (rated) Current drawn = 10
Power input = I0
Y_{0}=\frac{I_{0}}{V_{1}}, G_{i}=\frac{P_{0}}{V_{1}^{2}}
B_{m}=\sqrt{Y_{0}^{2}-G_{i}^{2}}
Short-Circuit Test The equivalent circuit as seen during short-circuit test is drawn in Fig. 3.23(b).
Applied voltage =V_{sc} (a fraction of rated value)
Current drawn = I_{sc} (nearly full load value)
Power input = P_{sc} = P_{c} (copper loss)
Z=\frac{V_{sc}}{I_{sc}} , R=\frac{P_{sc}}{(I_{sc})^{2}}
X=\sqrt{Z^{2}-R^{2}}
Voltage Regulation
% voltage regulation =\frac{voltage drop}{rated secondary voltage at full load and specified pf} \times 100
or, VR=\frac{I(R \cos \phi \pm X \sin \phi )}{V_{2}} \times 100; + for lagging pf;
– for leading pf
where
I = secondary current
R = equivalent resistance referred to secondary
X = equivalent reactance referred to secondary
\phi = power factor angle
Efficiency at full load
Efficiency at full load = \frac{Full load output\times 100}{Full load output + Core loss + Copper loss at full load} =\frac{P}{P+P_{i}+P_{c}} \times 100
MATLAB PROGRAM
P=50000;
V1=2200;
V2=110;
V0=110;
I0=10;
P0=400;
Y0=I0./V0
Gi=P0./(V0^2)
Bm=sqrt (Y0^2-Gi^2)
Vsc=90;
Isc=20.5;
Psc=808;
Z=Vsc./Isc
R=Psc./Isc^2)
X=sqrt (Z^2-R^2)
TR=2200/110;
Gi_HV=Gi./(TR^2)
Bm_HV=Bm./(TR^2)
R_LV=R./(TR^2)
X _LV=X./(TR^2)
I2=P./V2
pf=0.8;
Th=acos(pf)
dV=I2.*(R_LV.*cos(Th)+X_LV.*sin(Th))
VR=(dV./V2)*100
Pi=P0
Pc=Psc
EFF_Full_load=(P*100)./(P+Pi+Pc)
y0 =
0.0909
Gi =
0.0331
Bm =
0.0847
Z =
4.3902
R =
1.9227
X =
3.9468
Gi_HV =
8.2645e-005
Bm_HV =
2.1171e-004
R_LV =
0.0048
X_LV =
0.0099
I2 =
454.5455
Th =
0.6435
dV =
4.4389
VR =
4.0354
Pi =
400
Pc =
808
EFF_Full_load =
97.6410
Note For manual solution, refer solved Problem 3.3 of the Authors’ book [76]
^{ \dagger \dagger \dagger \dagger \dagger } For detailed write-up on MATLAB, the reader is encouraged to read Appendix G of the authors’ book “Modern Power System Analysis”, 3rd ed. Tata McGraw-Hill, New Delhi, 2003.