Suppose you are given the following values for KT for a location in the midwestern United States:Calculate g and graph F(KT) as a function of KT.

Question

Suppose you are given the following values for KT for a location in the midwestern United States:

Jan	0.41	Jul	0.68
Feb	0.45	Aug	0.67
Mar	0.51	Sep	0.66
Apr	0.55	Oct	0.59
May	0.61	Nov	0.44
Jun	0.67	Dec	0.38

Calculate g and graph F(K_T) as a function of K_T.

Accepted Answer

The values of K[latex]_{T,min}[/latex], K[latex]_{T,max}[/latex], and K are 0.38, 0.68, and 0.55, respectively. The best fit value for γ can be solved iteratively using software; solving to two decimal place, in this case using the Solver function in MS Excel, gives either γ = −1.12 × 10[latex]^{−7}[/latex] or γ = 3. The appropriate value must then be chosen based on observed conditions. For the case of γ = −1.12 × 10[latex]^{−7}[/latex], there is a 50% chance that the clearness will be less than or equal to 0.53, which implies relatively cloudy conditions. In the case of γ = 3, the value is only 39%, so that conditions are relatively sunny. From the given data, we see that 8 out of 12 months have values of K[latex]_T[/latex] in the range of 0.5 to 0.68, so γ = 3 is the correct value. Plotting F(K[latex]_T[/latex]) then gives the curve shown in Fig. 9-12.

Question 9.3: Suppose you are given the following values for KT for a loca...

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