The Combined Gas Law . A gas in a flexible container has a volume of 0.50 L and a pressure of 1.0 atm at 393 K. When the gas is heated to 500 K, its volume expands to 3.0 L. What is the new pressure of the gas in the flexible container?

Strategy : We identify the known quantities and then solve the combined gas law for the new pressure.

Question

The Combined Gas Law . A gas in a flexible container has a volume of 0.50 L and a pressure of 1.0 atm at 393 K. When the gas is heated to 500 K, its volume expands to 3.0 L. What is the new pressure of the gas in the flexible container?

Strategy : We identify the known quantities and then solve the combined gas law for the new pressure.

Accepted Answer

Step 1: The known quantities are

Initial: [latex]P_{1} = 1.0 atm[/latex] [latex]V_{1} = 0.50 L[/latex] [latex]T_{1} = 393 K[/latex]

Final: [latex]P_{2} = ?[/latex] [latex]V_{2} = 3.0 L[/latex] [latex]T_{2} = 500 K[/latex]

Step 2: Solve the combined gas law for [latex]P_{2}[/latex] , we find

[latex]P_{2} =\frac{P_{1} V_{1} T_{2} }{T_{1} V_{2}} =\frac{ (1.0 atm ) (0.50 \cancel{L})(500 \cancel{k})}{(3.0 \cancel{L})(393 \cancel{k})} = 0.21 atm[/latex]

Question 5.3: The Combined Gas Law . A gas in a flexible container has a v...

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