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Question 8.2.5: The current I is (a) 31.25 µA (b) 62.5 µA (c) 125 µA (d) 250...

The current I is

(a) 31.25 µA                                                           (b) 62.5 µA

(c) 125 µA                                                               (d) 250 µA

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VR = 10V, R = 10 kΩ                              V+ = 0, V– = 0

⇒i=VR2R=1̸02×1̸0k=0.5mA\Rightarrow i=\frac{V_{R}}{2 R}=\frac{\not{10}}{2 \times \not{10} k}=0.5 mA

 

I=i2×2×2=0.58=6.25μAI=\frac{i}{2 \times 2 \times 2}=\frac{0.5}{8}=6.25 \mu A

Hence, the correct option is (b).

8.5
8.5a
8.5

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