The electric field strength at a far-off point P due to a point charge, +q located at the origin, O is 100 millivolts/meter. The point charge is now enclosed by a perfectly conducting hollow metal sphere with its centre and the origin, O. The electric field strength at the point, P (a) remains unch

Question

The electric field strength at a far-off point P due to a point charge, +q located at the origin, O is 100 millivolts/meter. The point charge is now enclosed by a perfectly conducting hollow metal sphere with its centre and the origin, O. The electric field strength at the point, P

(a) remains unchanged in its magnitude and direction.

(b) remains unchanged in its magnitude but reverse in direction.

(c) would be that due to a dipole formed by the charge, +q, at O and -q induced.

(d) would be zero.

Accepted Answer

According to Gauss Law:—The total displacement or electric flux through any closed surface surrounding charges is equal to the amount of charge enclosed.

[latex]\oint D \cdot d s=2[/latex]

Here, total enclosed charge is, -q + q = 0 thus, D = 0 also, [latex]E=\frac{D}{E}=0[/latex]

Hence, the correct option is (d).

Question 1.2.29: The electric field strength at a far-off point P due to a po...

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