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Question 9.1: The following dimensions are given for a shelby tube sampler...

The following dimensions are given for a shelby tube sampler:

External diameter = 51 mm

Internal diameter = 48 mm

Determine the area ratio

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Per Eq (9.1) the area ratio A_{r} is

 

A_{r}=\frac{d_{o}^{2}-d_{i}^{2}}{d_{i}^{2}} \times 100 percent, (9.1)

 

A_{r}=\frac{d_{o}^{2}-d_{i}^{2}}{d_{i}^{2}}=\frac{51^{2}-48^{2}}{48^{2}}=0.129=12.9 \%

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