The lungs of an average male hold 0.25 mol of air in a volume of 5.8 L. How many moles of air do the lungs of an average female hold if the volume is 4.6 L?

Question

The lungs of an average male hold 0.25 mol of air in a volume of 5.8 L. How many moles of air do the lungs of an average female hold if the volume is 4.6 L?
Analysis
This question deals with volume and number of moles, so Avogadro’s law is used to determine a final number of moles when three quantities are known—the initial volume and number of moles ([latex]V_{1} and n_{1}[/latex]), and the final volume ([latex]V_{2}[/latex]).

Accepted Answer

[1] Identify the known quantities and the desired quantity.

[latex]V_{1}[/latex] = 5.8 L [latex]V_{2}[/latex]= 4.6 L
[latex]n_{1}[/latex]= 0.25 mol [latex]n_{2}[/latex]= ?
known quantities desired quantity

[2] Write the equation and rearrange it to isolate the desired quantity, [latex]n_{2}[/latex], on one side.
• Use Avogadro’s law. To solve for [latex]n_{2}[/latex], we must invert the numerator and denominator on both sides of the equation, and then multiply by [latex]V_{2}[/latex].

[3] Solve the problem.
• Substitute the three known quantities into the equation and solve for [latex]n_{2}[/latex].

Question 6..sp.6: The lungs of an average male hold 0.25 mol of air in a volum...

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