Question 1.6: The pressure at the deepest part of the ocean is approximate...

The pressure at the deepest part of the ocean is approximately 1100 atm. Estimate the density of seawater in slug/ft^3 at this pressure.

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Equation (1.19)
\frac{p}{p_{a}} \approx (B+1) (\frac{\rho }{\rho_{a}} )^n -B
holds for either water or seawater. The ratio p/p_{a} is given as 1100 :
1100 \approx (3001)(\frac{\rho }{\rho_{a} } )^7 -3000
or \frac{\rho }{\rho_{a} }= (\frac{4100}{3001} )^{1/7}=1.046
Assuming an average surface seawater density \rho_{a}= 2.00 slugs/ft^3 , we compute
\rho \approx 1.046(2.00)=2.09 slugs/ft^3
Even at these immense pressures, the density increase is less than 5 percent, which justifies
the treatment of a liquid flow as essentially incompressible.

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