The secondary winding of a transformer possesses 180 turns. When the transformer is under load, the secondary current has an effective value of 18 A, 60 Hz. Furthermore, the mutual mhas a peak value of 20 mWb. The secondary leakage flux f2 has a peak value of 3 mWb. Calculate a. The voltage

Question

The secondary winding of a transformer possesses 180 turns. When the transformer is under load, the secondary current has an effective value of 18 A, 60 Hz. Furthermore, the mutual $\Phi_{ m }$ has a peak value of 20 mWb. The secondary leakage flux $\Phi_{ f 2}$ has a peak value of 3 mWb.

Calculate
a. The voltage induced in the secondary winding by its leakage flux
b. The value of the secondary leakage reactance
c. The value of $E_{2}$ induced by the mutual flux $\Phi_{ m }$

Calculate
a. The voltage induced in the secondary winding by its leakage flux
b. The value of the secondary leakage reactance
c. The value of [latex]E_{2}[/latex] induced by the mutual flux [latex]\Phi_{ m }[/latex]

Accepted Answer

a. The effective voltage induced by the secondary leakage flux is

[latex]\begin{aligned}E_{ f 2} &=4.44 f N_{2} \Phi_{ f 2} \&=4.44 imes 60 imes 180 imes 0.003 \&=143.9 V\end{aligned}[/latex]

b. The secondary leakage reactance is

[latex]\begin{aligned}X_{ f 2} &=E_{ f 2} / I_{2} \&=143.9 / 18 \&=8 \Omega\end{aligned}[/latex]

c. The voltage induced by the mutual flux is

[latex]\begin{aligned}E_{2} &=4.44 f N_{2} \Phi_{ m } \&=4.44 imes 60 imes 180 imes 0.02 \&=959 V\end{aligned}[/latex]

Question 10.2: The secondary winding of a transformer possesses 180 turns. ...

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