The voltage V_{0} is
(a) − 0.781 V (b) − 1.562 V
(c) − 3.125 V (d) − 6.250 V
Question 8.2.6: The voltage V0 is (a) − 0.781 V (b) − 1.562 V (c) − 3.125 V ...
Inverting terminal:
\text { Inverting }=\frac{i}{2}+\frac{i}{8}=\frac{5 i}{8}=\frac{5 \times 0.5}{8} mA= 3.12.5 μA
\text { Now } \quad V_{0}=-R \times I_{\text {inv }}
\begin{aligned}&=-10 k \times 3.125 \mu A \\&=-3.12 .5 \times 104 \times 10^{-6} \\V_{0} &=-3.125 V\end{aligned}
Hence, the correct option is (c).
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