Use Theorem 10 to find the least-squares solution of Ax = b, where
A=\left[\begin{array}{rr}1 & -2 / 3 \\-1 & 3 \\0 & -2 \\-1 & 1 \\1 & 0\end{array}\right] \text { and } b =\left[\begin{array}{r}1 \\3 \\-4 \\-3 \\3\end{array}\right].
Use Theorem 10 to find the least-squares solution of Ax = b, where
A=\left[\begin{array}{rr}1 & -2 / 3 \\-1 & 3 \\0 & -2 \\-1 & 1 \\1 & 0\end{array}\right] \text { and } b =\left[\begin{array}{r}1 \\3 \\-4 \\-3 \\3\end{array}\right].