Using Boolean algebra, prove that
(a) (A+B)(\overline{A}\overline{C}+C)\overline{(\overline{B}+AC)} = \overline{A}B
(b) (A+B)(\overline{AC} +C)\overline{(\overline{B}+AC)}= \overline{A}B
(c) (A+B)(\overline{A}+C) = AC+\overline{A}B+BC
Using Boolean algebra, prove that
(a) (A+B)(\overline{A}\overline{C}+C)\overline{(\overline{B}+AC)} = \overline{A}B
(b) (A+B)(\overline{AC} +C)\overline{(\overline{B}+AC)}= \overline{A}B
(c) (A+B)(\overline{A}+C) = AC+\overline{A}B+BC