Question 14.6: What is the molarity of a solution containing 1.4 mol of ace...

By the unit-conversion method, we note that the concentration given in the problem statement is 1.4 mol per 250. mL (mol/mL). Since molarity = mol/L, the needed conversion is

Solution map: $\frac{mol}{mL}$ →$\frac{mol}{L}$ =M

CALCULATE  $(\frac{1.4   mol}{250.  \cancel{mL}})  (\frac{1000  \cancel{mL} }{L}) = \frac{5.6   mol}{L}=$ 5.6 M