Question 6.29: You are asked to referee a grant application, which proposes...

You are asked to referee a grant application, which proposes to determine whether the magnetization of iron is due to “Ampère” dipoles (current loops) or “Gilbert” dipoles (separated magnetic monopoles). The experiment will involve a cylinder of iron (radius R and length L = 10R), uniformly magnetized along the direction of its axis. If the dipoles are Ampère-type, the magnetization is equivalent to a surface bound current K _{b}=M \hat{\phi} ; if they are Gilbert-type, the magnetization is equivalent to surface monopole densities \sigma_{b}=\pm M at the two ends. Unfortunately, these two configurations produce identical magnetic fields, at exterior points. However, the interior fields are radically different—in the first case B is in the same general direction as M, whereas in the second it is roughly opposite to M. The applicant proposes to measure this internal field by carving out a small cavity and finding the torque on a tiny compass needle placed inside. 

Assuming that the obvious technical difficulties can be overcome, and that the question itself is worthy of study, would you advise funding this experiment? If so, what shape cavity would you recommend? If not, what is wrong with the proposal? [Hint: Refer to Probs. 4.11, 4.16, 6.9, and 6.13.]

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The problem is that the field inside a cavity is not the same as the field in the material itself.

(a) \text { Ampére } type. The field deep inside the magnet is that of a long solenoid, B _{0} \approx \mu_{0} M . From Prob. 6.13

\left\{\begin{array}{l}\text { Sphere }: B = B _{0}-\frac{2}{3} \mu_{0} M =\frac{1}{3} \mu_{0} M ;\\\text { Needle }: B = B _{0}-\mu_{0} M =0; \\\text { Wafer : } B =\mu_{0} M.\end{array}\right.

(b) Gilbert type. This is analogous to the electric case. The field at the center is approximately that midway between two distant point charges, B _{0} \approx 0 . From Prob. 4.16 (with E \rightarrow B , 1 / \epsilon_{0} \rightarrow \mu_{0}, P \rightarrow M ): 

\left\{\begin{array}{l}\text { Sphere }: B = B _{0}+\frac{\mu_{0}}{3} M =\frac{1}{3} \mu_{0} M; \\\text { Needle }: B = B _{0}=0; \\\text { Wafer : } B = B _{0}+\mu_{0} M =\mu_{0} M. \end{array}\right.

In the cavities, then, the fields are the same for the two models, and this will be no test at all. Yes. Fund it with $1 M from the O!ce of Alternative Medicine.

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