Question 10.14: Analysis Using Root Locus Refer to the root locus obtained i...
Analysis Using Root Locus
Refer to the root locus obtained in Example 10.13. Comment on the stability and performance of the closed-loop system when K varies from 0 to \infty.
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When K=0, which corresponds to having no control, the root locus starts from the poles of the loop gain L(s). As shown in Figure 10.51, all four open-loop poles are located in the left s-plane. This implies that the open-loop system is stable. As K increases, the four closed-loop poles move along four different branches of the root locus. For 0 \leq K<60.91, all of the poles are in the left-half s-plane, and thus the closed-loop system is stable. When K=60.91, two complex poles, \pm 3.44 \mathrm{j}, appear on the imaginary axis, and thus the closed-loop system becomes marginally stable. For K> 60.91, the two complex branches of the root locus cross the imaginary axis and enter the right-half s-plane and the closed-loop system becomes unstable.
When K varies between 0 and 60.91 , the pair of complex poles is always closer to the origin than the other poles. Consequently, they dominate the effects of all other poles and thus the closed-loop system exhibits underdamped oscillations. For example, the closed-loop poles are -3.29,-1.66, and -1.03 \pm 1.15 \mathrm{j} when K=1. Figure 10.52 is the corresponding closed-loop unit-step response, which has an overshoot of 21.1 \%. As K increases, the closed-loop system will exhibit severe oscillations because the dominant complex poles move toward the imaginary axis and the damping decreases. For example, the closed-loop poles are -5.16,-1.06, and -0.39 \pm 2.74 j when K=30. Figure 10.53 is the corresponding closed-loop unit-step response, in which the overshoot is as high as 110 \%.


