A flywheel of 100 kg mass and 350 mm radius of gyration is rotating at 500 rpm. It is brought to rest by means of a brake. The mass of the brake drum assembly is 5 kg. The brake drum is made of cast-iron FG260(c = 460 J/kg°C ). Assuming that the total heat generated is absorbed by the brake drum only, calculate the temperature rise.
Question 12.14: A flywheel of 100 kg mass and 350 mm radius of gyration is r...
Given For brake assembly, m = 5 kg
c = 460 J/kg°C For flywheel, m = 100 kg
k = 350 mm n = 500 rpm
Step I KE of flywheel
\omega_{1}=\frac{2 \pi n_{1}}{60}=\frac{2 \pi(500)}{60}=52.36 rad / s \text { and } w_{2}=0 .
KE =\frac{1}{2} m k^{2}\left(\omega_{1}^{2}-\omega_{2}^{2}\right)=\frac{1}{2}(100)(0.35)^{2}(52.36)^{2} .
=167921 J .
Step II Temperature rise
\therefore \quad \Delta_{t}=\frac{E}{m c}=\frac{167921}{5(460)}=73^{\circ} C .
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