Question 6.8: Malfunction of a Refrigerator Light Switch The interior ligh...

Malfunction of a Refrigerator Light Switch The interior lighting of refrigerators is provided by incandescent lamps whose switches are actuated by the opening of the refrigerator door. Consider a refrigerator whose 40-W lightbulb remains on continuously as a result of a malfunction of the switch (Fig. 6–58). If the refrigerator has a coefficient of performance of 1.3 and the cost of electricity is 8 cents per kWh, determine the increase in the energy consumption of the refrigerator and its cost per year if the switch is not fixed.

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The lightbulb of a refrigerator malfunctions and remains on. The increases in the electricity consumption and cost are to be determined.
Assumptions The life of the lightbulb is more than 1 year.
Analysis The lightbulb consumes 40 W of power when it is on, and thus adds 40 W to the heat load of the refrigerator. Noting that the COP of the refrigerator is 1.3, the power consumed by the refrigerator to remove the heat generated by the lightbulb is

\dot{W}_{\text {refrig }}=\frac{\dot{Q}_{\text {refrig }}}{ COP _{ R }}=\frac{40 W }{1.3}=30.8 W

Therefore, the total additional power consumed by the refrigerator is

\dot{W}_{\text {total,additional }}=\dot{W}_{\text {light }}+\dot{W}_{\text {refrig }}=40+30.8=70.8 W

The total number of hours in a year is

\text { Annual hours }=(365 \text { days } / yr )(24 h / \text { day })=8760 h / yr

Assuming the refrigerator is opened 20 times a day for an average of 30 s, the light would normally be on for

\begin{aligned}\text { Normal operating hours } &=(20 \text { times/day })(30 s / \text { time })(1 h / 3600 s )(365 \text { days } / yr ) \\&=61 h / yr\end{aligned}

Then the additional hours the light remains on as a result of the malfunction becomes

Additional operating hours = Annual hours – Normal operating hours

= 8760 – 61 = 8699 h/yr

Therefore, the additional electric power consumption and its cost per year are

\begin{aligned}\text { Additional power consumption } &=\dot{W}_{\text {total,additional }} \times \text { (Additional operating hours) } \\&=(0.0708 kW )(8699 h / yr )= 6 1 6 ~ k W h / y r\end{aligned}

and

\begin{aligned}\text { Additional power cost } &=\text { (Additional power consumption) }(\text { Unit cost }) \\&=(616 kWh / yr )(\$ 0.08 / kWh )=\$ 49.3 / yr\end{aligned}

Discussion Note that not repairing the switch will cost the homeowner about $50 a year. This is alarming when we consider that at $0.08/kWh, a typical refrigerator consumes about $70 worth of electricity a year.

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