Question 7.19: Consider the circuit in Fig. 7.73, and assume that R1 = 1.5M...
Consider the circuit in Fig. 7.73, and assume that R1=1.5MΩ, 0 < R < 2.5 MΩ. (a) Calculate the extreme limits of the time constant of the circuit. (b) How long does it take for the lamp to glow for the first time after the switch is closed? Let R2 assume its largest value.

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(a) The smallest value for R2 is 0 Ω, and the corresponding time constant for the circuit is
τ=(R1+R2)C=(1.5×106+0)×0.1×10−6=0.15sThe largest value for R2 is 2.5 MΩ, and the corresponding time constant for the circuit is
τ=(R1+R2)C=(1.5+2.5)×106×0.1×10−6=0.4sThus, by proper circuit design, the time constant can be adjusted to introduce a proper time delay in the circuit.
(b) Assuming that the capacitor is initially uncharged, vC(0)=0, while vC(∞)=110. But
where τ = 0.4 s, as calculated in part (a). The lamp glows when vC=70V . If vC(t)=70V at t=t0, then
70=110[1−e−t0/τ]⟹117=1−e−t0/τor
e−t0/τ=114⟹et0/τ=411Taking the natural logarithm of both sides gives
t0=τln411=0.4ln2.75=0.4046sA more general formula for finding t0 is
t0=τlnv(t0)−v(∞)v(0)−v(∞)The lamp will fire repeatedly every τ seconds if and only if t0<τ. In this example, that condition is not satisfied.