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Question 2.6.8: A force of 1000.0 N acts on a body of 40.0 kg initially at r...

A force of 1000.0 N acts on a body of 40.0 kg initially at rest for a time interval of 0.0500 s. What is the velocity of the mass?

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The impulse is

F Δt = 1000 × 0.05 N s

= 50.0 N s

and this equals the amount by which the body’s momentum increases. The velocity is thus

\frac{50}{40} m s ^{-1}=1.25 m s ^{-1}

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