Question H3.1: Find the speed of a particle whose total energy is double it...
Find the speed of a particle whose total energy is double its rest energy.
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We have that
\begin{aligned}E &=\gamma m_{0} c^{2} \\2 m_{0} c^{2} &=\gamma m_{0} c^{2} \\\Rightarrow \gamma &=2\end{aligned}\Rightarrow \sqrt{1-\frac{v^{2}}{c^{2}}}=\frac{1}{2}
\Rightarrow 1-\frac{v^{2}}{c^{2}}=\frac{1}{4}
\Rightarrow \frac{v^{2}}{c^{2}}=\frac{3}{4}
\Rightarrow v=\frac{\sqrt{3}}{2} c=0.866 c
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