Question 8.7: The [OH^-] of a strongly basic solution is 1.0 × 10^-2. What...
The [OH^{-}] of a strongly basic solution is 1.0 × 10^{-2}. What are the pOH and pH of this solution?
Strategy
When given the [OH^{-}], determine the pOH by taking the negative
logarithm. To calculate the pH, subtract the pOH from 14.
The pOH is -log 1.0 × 10^{-2} or 2.00, and the pH is 14.00 – 2.00 = 12.00.
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