Question 4.22: The following masses, in grams, were recorded in an experime...

To begin with, place the masses in order from smallest to largest

2.514      3.039   3.048   3.049   3.067   3.079   3.094   3.102   3.109

and calculate Q_{exp}

Q_{exp}=\frac{X_2-X_1}{X_9-X_1}=\frac{3.039-2.514}{3.109-2.514} =0.882

The critical value for Q(0.05, 9) is 0.493. Since Q_{exp} > Q(0.05, 9) the value is assumed to be an outlier, and can be rejected.