Question 1.3: 30 kg of oil has been poured in the cubical tank with all si......

Given

Mass of oil = 30 kg

Length of side of cubical tank = 0.3 m

Volume of tank, V = (0.3)³ m³

= 0.027 m³

So, mass density,

\begin{aligned} \rho & =\frac{m}{V}=\frac{30}{0.027} \\ & =1111.11  kg / m ^3 \end{aligned}

Specific gravity,

\begin{aligned} G & =\frac{\rho_{\text {oil }}}{\rho_{\text {water }}} \\ G & =\frac{1111.11}{1000}=1.111 \end{aligned}