Specific gravity of ethyl alcohol is 0.75. Calculate its mass density and weight density.
Given,
G = 0.75
Since, G=\frac{\rho_{\text {alchohol }}}{\rho_{\text {water }}}
\begin{aligned} \rho_{\text {alchohol }} & =G \times \rho_{\text {water }} \\ & =0.75 \times 1000=750 kg / m ^3 \end{aligned}
Weight density will be
\gamma_{\text {alchohol }}=\rho_{\text {alchohol }} \times g
= 750 × 9.81 = 7357.5 N
= 7.357 kN