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Question 5.SSE.12: A compound D (C8H10O) upon treatment with alkaline solution ......

A compound D ( C_8H_{10}O ) upon treatment with alkaline solution of iodine gives a yellow precipitate. The filtrate on acidification gives a white solid E ( C_7H_6O_2 ). Write the structures of D, E and explain the formation of E.

[IIT, 1996]

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\begin{matrix} \text {Compound (D)} & \left( C _8 H _{10} O \right) & \overset{I _2+ NaOH}{\xrightarrow {\hspace{2 cm}} } & CHI _3 \downarrow &+& \text { Compound } & \overset{\text {Acid}}{\underset{\left( C _7 H _6 O _2\right)}{\xrightarrow {\hspace{2 cm}} }} & \text { Compound E} \\ &&& \text {Yellow ppt.} && \text {(fiIterate)}\end{matrix} 

This reaction indicates the presence of – COCH _3 group in given compound D or presence of – CHOH – CH _3 group in given compound D. On the basis molecular formula of compound D and above reaction,the possible structure is given below:

This compound gives iodoform test as in following reaction. (In it in first step this compound on oxidation with I_2 gives

 

\begin{matrix} CH &-& CH _3&+&3 I _2&+&4 NaOH & \longrightarrow \\ | \\ OH \\\\\\\\ \end{matrix} 

\begin{matrix} COONa &+&5 Nai &+&5 H _2 O &+& CHI _3 \downarrow \\ &&&&&& \text {yellowish} \\ &&&&&& \text {crystalline solid}\\ \end{matrix}

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