A compound has the molecular formula C_{10} H_{14}. It gives the following NMR data.
(i) 0.88 δ (9 H singlet)
(ii) 7.28 δ (5 H, singlet, aromatic protons)
Assign structure to the compounds
(i) A nine proton singlet at 0.88 δ indicates the presence of a tertiary butyl group.
(ii) Five proton singlet at 7.28 δ confirms phenyl ring.
Hence the structural formula of the compound may be
\begin{matrix} & &CH_3 & & \\ & & | & & \\ \begin{matrix} &—— & \\ \quad \diagup \diagup & & \diagdown \diagdown \quad \\ \diagdown & & \diagup & \\ & \overset{——}{—— }& & \end{matrix} & —& C &—&CH_3\\ & & | & & \\ & & CH_3& & \end{matrix}