## Q. 2.2

A hollow pipe of inside diameter 40 mm and outside diameter 50 mm is compressed by an axial force of 55 kN. Calculate compressive stress in the material of the pipe.

## Verified Solution

This problem is also straightforward as the previous one. The problem is sketched in Figure 2.16.

The resisting area is (annular portion) $=\frac{\pi}{4}\left(50^2-40^2\right)$

= 706.85 mm²

The normal stress $=\sigma=\frac{55 \times 10^3}{706.85}$

= 77.80 N/mm².