Chapter 2
Q. 2.2
A hollow pipe of inside diameter 40 mm and outside diameter 50 mm is compressed by an axial force of 55 kN. Calculate compressive stress in the material of the pipe.
Step-by-Step
Verified Solution
This problem is also straightforward as the previous one. The problem is sketched in Figure 2.16.
The resisting area is (annular portion) =\frac{\pi}{4}\left(50^2-40^2\right)
= 706.85 mm²
The normal stress =\sigma=\frac{55 \times 10^3}{706.85}
= 77.80 N/mm².
