Question 10.7.1: A hydraulic press has a ram of 200 mm diameter and a plunger......
A hydraulic press has a ram of 200 mm diameter and a plunger of 30 mm diameter. It is used for lifting a weight of 3 kN. Find the force required at the plunger. How much force will be required at the end of a lever, if used, having the ratio l/L = 1/10. If the stroke of the plunger is 100 mm find the distance travelled by the weight in 100 strokes. Determine the work done.
Given: A = 0.7854 × 0.2^2 = 0.0314 m^2, a = 0.7854 × 0.03^2 = 7.068 × 10^{–4}, W = 3000 N, l/L = 0.1
Force required at the plunger = (a/A) × W = 67.52 N
From Eq. 10.6.1, force required at the end of the lever = P = 6.752 N
W = load lifted =p \times A =P \times \frac{L}{l}\times \frac{A}{a} (10.7.1)
Displacement of the load is obtained by calculating the displacement of the liquid by movement of the plunger in 100 strokes. This gives
Volume of the displaced liquid = 100 × 0.1 × a = 0.007068 m³
∴ Load displacement = 0.007068/A = 0.2251 m