The efficiency of a hydraulic crane, which is supplied water under a pressure of 70 N/cm² for lifting a weight through a height of 10 m, is 60%. If the diameter of the ram is 150 mm and velocity ratio 1/6, find (i) the weight lifted, and (ii) the volume of water required in litres to lift the weight.
Given: η_c = 0.6, p = 7 × 10^5 N/m^2, x = 10 m, D = 0.15 m → A = 0.0176 m^2 \text{and} F = p ×A = 12369 N, VR = 1/6
\eta _c=\frac{W\times \mathrm{distance moved by weight}}{F\times y} =\frac{W}{F\times VR} \rightarrow W=1236.9 N
Volume of water required for lift = A × y = 0.0176 × 10/6 = 0.0945 m³ = 29.45 l