A sine wave has a maximum voltage of 350 V. At what angle of rotation will the voltage reach 53 V?
\mathrm{sin \angle \theta}=\frac{\mathrm{E_{(INST)}}}{E_{\mathrm{(MAX)}}}
\mathrm{sin \angle \theta}=\frac{53\ V}{350\ V}
\mathrm{sin \angle \theta}= 0.151
Note: 0.151 is the sine of the angle, not the angle.
\angle \theta = 8.685°