Question 10.12: A single-phase motor is located 250 ft from its power source......

\mathrm{E}_{\mathrm{D}}=\frac{2 \times 10.4 ~\Omega-\mathrm{CM} / \mathrm{ft} \times 24 \mathrm{~A} \times 250 ~\mathrm{ft}}{10,380 ~\mathrm{CM}}

E_D=12.023 \mathrm{~V}

A slightly different formula can be used to compute the voltage drop on a three-phase system. Instead of multiplying KIL by 2, multiply KIL by the square root of 3:

E_D=\frac{\sqrt{3} ~\mathrm{KIL}}{C M}