Question 18.p.10: a) The ions are K^+ and ClO2^-; the K^+ is from the strong b......
a) The ions are \text{K}^+\text{ and ClO}_2^-; \text{the K}^+ is from the strong base KOH, and does not react with water. The \text{ClO}_2^-\text{ is from the weak acid HClO}_2, so it reacts with water to produce \text{OH}^- ions.
b) The ions are \text{CH}_3\text{NH}_3^+\text{ and NO}_3^-; \text{CH}_3\text{NH}_3^+ is derived from the weak base methylamine, \text{CH}_3\text{NH}_2. Nitrate ion, \text{NO}_3^-, is derived from the strong acid \text{HNO}_3 (nitric acid).
c) The ions are \text{Cs}^+\text{ and I}^-. Cesium ion is derived from cesium hydroxide, CsOH, which is a strong base because Cs is a Group 1 A( 1) metal. Iodide ion is derived from hydroiodic acid, HI, a strong hydrohalic acid.
a) Since the base is strong and the acid is weak, the salt derived from this combination will produce a basic solution.
\text{K}^+ does not react with water
\text{ClO}_2^-(aq) + \text{H}_2\text{O}(l) \leftrightarrows \text{HClO}_2(aq) + \text{OH}^-(aq)
b) A salt derived from a weak base and strong acid produces an acidic solution.
\text{NO}_3^- does not react with water
\text{CH}_3\text{NH}_3^+(aq) + \text{H}_2\text{O}(l) \leftrightarrows \text{CH}_3\text{NH}_2(aq) + \text{H}_3\text{O}^+(aq)
c) Since both the base and acid are strong, the salt derived from this combination will produce a neutral solution.
Neither \text{Cs}^+\text{ nor I}^- react with water.