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Question 18.34: Write total ionic equations and then remove the spectator io......

Write total ionic equations and then remove the spectator ions to write the net ionic equations. The (aq) subscript denotes that each species is soluble and dissociates in water.

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\text{a) }\sout{\text{Na}}^+(\sout{aq})+\text{OH}^-(aq)+\sout{\text{Na}}^+(\sout{aq})+\text{H}_2\text{PO}_4^-(aq)\leftrightarrows \text{H}_2\text{O}(l)+\sout{2\text{ Na}}^+(\sout{aq})+\text{HPO}_4^{2-}(aq) \\ \begin{matrix} \text{Net: OH}^-(aq)+ & \text{H}_2\text{PO}_4^-(aq)\leftrightarrows & \text{H}_2\text{O}(l)+ & \text{HPO}_4^{2-}(aq) \\ \text{base} & \text{acid} & \text{conjugate acid} & \text{conjugate base} \end{matrix}

Conjugate acid/base pairs: \text{H}_2\text{PO}_4^-/ \text{HPO}_4^{2-}\text{ and H}_2\text{O/OH}^- \\ \text{b) }\sout{\text{K}}^+(\sout{aq})+\text{HSO}_4^-(aq)+\sout{\text{2 K}}^+(\sout{aq})+\text{CO}_3^{2-}(aq)\leftrightarrows \sout{\text{2 K}}^+(\sout{aq})\text{SO}_4^{2-}(aq)+\sout{\text{K}}^+(\sout{aq})+\text{HCO}_3^-(aq) \\ \begin{matrix}\text{Net: HSO}_4^-(aq)+&\text{CO}_3^{2-}(aq)\leftrightarrows & \text{SO}_4^{2-}(aq) &+& \text{HCO}_3^-(aq) \\ \text{acid}&\text{base}&\text{conjugate base} && \text{conjugate acid} \end{matrix}

Conjugate acid/base pairs: \text{HSO}_4^-/\text{SO}_4^{2-}\text{ and HCO}_3^-/\text{CO}_3^{2-}

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