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Question 7.P.1: A time study analyst timed an assembly operation for 30 cycl......

A time study analyst timed an assembly operation for 30 cycles, and then computed the average time per cycle, which was 18.75 minutes. The analyst assigned a performance rating of .96, and decided that an appropriate allowance was 15 percent. Assume the allowance factor is based on the workday. Determine the following: the observed time (OT), the normal time (NT), and the standard time (ST).

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OT = Average time = 18.75 minutes
NT = OT × Performance rating = 18.75 minutes × .96 = 18 minutes

\mathrm{AF}\,=\,{\frac{1}{1-{A}}}\,=\,{\frac{1}{1\,-\,.15}}\,=\,1.176\\ \mathrm{ST}\,=\,\mathrm{NT}\times\,\mathrm{AF}\,=\,18\times1.176\,=\,21.17\,\mathrm{\ minutes}

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