An amplifier has a voltage gain of 10, an infinite input resistance and zero output resistance. The amplifier is connected, as in Example 14.1, to a sensor that produces a voltage of 2 V and has an output resistance of 100 Ω, and to a load resistance of 50 Ω. What will be the output voltage of the amplifier?
As before, we first draw an equivalent circuit of the amplifier, sensor and load.
From the diagram
V_{i} = \frac{R_{i}}{R_{s} + R_{i}} V_{s}When R_{i} is much larger than R_{s} , this approximates to
V_{i} = \frac{R_{i}}{R_{s} + R_{i}} V_{s} ≈ \frac{R_{i}}{R_{i}} V_{s}In this case, R_{i} is infinite, so we can say
V_{i} = \frac{R_{i}}{R_{i}} V_{s} = V_{s} = 2 Vand, therefore, the output voltage is given by
V_{0} = A_{v} V_{i} \frac{R_{L}}{R_{0} + R_{L}} = 10 V_{i} \frac {50 Ω}{0 + 50 Ω} = 10 V_{i} = 10×2 = 20 VThe arrangement now has a voltage gain of 10 and there are no loading effects.