Question 15.11: An equilibrium mixture of the following reaction has [I] = 0......
An equilibrium mixture of the following reaction has
[I] = 0.075 M and \left[I_{2}\right] = 0.88 M.
What is the value of the equilibrium constant?
\,I_{2}(g)\rightleftarrows2\,I(g)
GIVEN: [I] = 0.075 M
\left[I_{2}\right] = 0.88 M
FIND: K_{eq}
Step-by-Step
K_{\mathrm{eq}}={\frac{[I]^{2}}{[I_{2}]}}
={\frac{[0.075]^{2}}{[0.88]}}
= 0.0064
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