Calculate the molar solubility of AgI.
K_{\mathrm{sp}}=[\mathrm{A}{\mathrm{g}}^{+}][\mathrm{I}^{-}]
S=[\mathrm{A}{\mathrm{g}}^{+}]=[\mathrm{I}^{-}]
K_{\mathrm{sp}}=[\mathrm{A}{\mathrm{g}}^{+}][\mathrm{I}^{-}]
= S\times S
= S^{2}
S={\sqrt{K_{\mathrm{sp}}}}
S=\sqrt{8.51\times10^{-17}}
= 9.22\times10^{-9}\,\mathrm{M}