Question 13.2: An inductor has a maximum current flow of 1.25 amperes. When......
An inductor has a maximum current flow of 1.25 amperes. When power is first applied to the inductor, how much current will flow at the end of the third time constant?
Step-by-Step
1.25 × 0.950 = 1.1875 A
When power is interrupted to an inductor, the current will decay at an exponential rate also. The RL current decay rate is shown in Table 13–2
| RL current Decay table | |
| time constant | Multiplication Factor |
| 1 | 0.368 \times I_{Max} |
| 2 | 0.135 \times I_{Max} |
| 3 | 0.050 \times I_{Max} |
| 4 | 0.019 \times I_{Max} |
| 5 | 0.008 \times I_{Max} |
TABLE 13–2 RL Current Decay Table
Related Answered Questions
Question: 13.3
Verified Answer:
4 × 0.135 = 0.54 A
Question: 13.1
Verified Answer:
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