At what rate must funds be continuously added to a savings account in order to accumulate $10 000 in 15 years, if interest is paid at 5% per year, compounded continuously?
By (5.10),
\bar{A}/F = \frac{r}{e^m – 1} (5.10) \\\\ \bar{A} = \$10 000\frac{0.05}{e^{(0.05)(15)} – 1} = \$447.63 per year
that is, $447.63 must flow uniformly into the account each year.
It is interesting to compare this result to a series of uniform, end-of-year payments, with interest compounded continuously as above. The amount of each such payment is given by (5.5) as
A/F = \frac{e^r – 1}{e^m – 1} (5.5)A = $10 000[A/F, 5%, 15] = $10 000(0.0459) = $459 per year
Thus, an additional $11.37 would be required each year if the payments were made annually rather than continuously.