Suppose that $2000 is deposited each year, on a continuous basis, into a savings account that pays 6% per year, compounded continuously. How much money will have accumulated after 12 years?
With \bar{A} = $2000 per year, (5.9) gives
\\\\ F = \bar{A}\frac{e^m – 1}{r} (5.9) \\\\ = \$2000\frac{e^{(0.06)(12)} – 1}{0.06} = \$2000(17.5739) = \$35 147.77Alternatively, using the tabular values in Appendixes C and D,
F = $2000[A/\bar{A}, 6%] [F/A, 6%, 12] = $2000(1.030609)(17.0519) = $35 147.68