Baseball All-Star Winners
The data show the winners of the baseball all-star games (\mathrm{N}= National League, \mathrm{A}= American League) from 1962 to 2012. At \alpha=0.05, can it be concluded that the sequence of winners is random?
\begin{array}{c}A&N&N&N&N&N&N&N&N&A\\ N&N&N&N&N&N&N&N&N&N\\ N&A&N&N&A&N&A&A&A&A\\ A&A&N&N&N&A&A&A&A&A\\ A&A&A&A&A&A&A&N&N&N\end{array}
(Note: The tie in 2002 has been omitted.)
Step 1 State the hypotheses and identify the claim.
H_{0} : The winners occur at random (claim).
H_{1} : The winners do not occur at random.
Step 2 Determine the actual values.
Since n_{1}>20 and n_{2}>20, Table E is used. At \alpha=0.05, the critical values are \pm 1.96.
Step 3 Find the test value.
n_{1}(\text { National })=28 \quad n_{2}(\text { American })=22
The number of runs is
1. A
2. NNNNNNNN
3. A
4. NNNNNNNNNNN
5. A
6. NN
7. A
8. N
9. AAAAAA
10. NNN
11. AAAAAAAAAAAA
12. NNN
There are G=12 runs.
\begin{aligned} \mu_{G} & =\frac{2 n_{1} n_{2}}{n_{1}+n_{2}}+1 \\ & =\frac{2(28)(22)}{28+22}+1=25.64 \\ \sigma_{G} & =\sqrt{\frac{2 n_{1} n_{2}\left(2 n_{1} n_{2}-n_{1}-n_{2}\right)}{\left(n_{1}+n_{2}\right)^{2}\left(n_{1}+n_{2}-1\right)}} \\ & =\sqrt{\frac{2(28)(22)[2(28)(22)-28-22]}{(28+22)^{2}(28+22-1)}}=3.448 \\ z & =\frac{G-\mu_{G}}{\sigma_{G}} \\ & =\frac{12-25.64}{3.448} \\ & =-3.96 \end{aligned}
Step 4 Make the decision. Since -3.96<-1.96, the decision is to reject the null hypothesis.
Step 5 Summarize the results. There is enough evidence to reject the claim that the sequence of winners occurs at random.