Calculate the bed slope of a trapezoidal channel of bed width 6 m and horizontal to vertical side slope of 1:3. Water flows at the rate of 10 m³/s at a depth of 2 m. Assume Chezy’s constant as 50.
Discharge Q=A C\ \sqrt{R_{h}}\ S_{b}
A=2\times\left[6+(2/3)\right]=13.3333\ \mathrm{m^{2}}, \\ P=6+\left({\sqrt{\textstyle2^{2}}}+(2/3)^{2}\right)^{2}=10.2164\mathrm{~m} \\ R_{h}=A/P=13.3333/10.2164=1.3051\mathrm{\ m} \\ 10=13.3333\times50\ \sqrt{1.3051\times S_{b}}\cdot{\mathrm{Solving,}}\ {\mathrm{S}}_{\mathrm{b}}=1/5800