Check if the grammar shown above on p. 202 (having nonterminals E, T and F) is an SLR(1)-grammar.
Yes; both conflicts that prevent it from being a LR(0)-grammar are resolved when we take the next input symbol into account. Indeed, for both T and E+T a shift is possible only when Next = ∗, and the symbol ∗ belongs neither to Follow(E) = {EOI, +, ) } nor to Follow(T) = {{EOI, +, ∗, ) }. Therefore, reduction is impossible when Next = ∗.