Convert 14 397 to a hexadecimal number.
From Table 1.3 the highest number that does not exceed 14 397 is 4096. We write
14397=3(4096)+2109We now focus on the 2109. From Table 1.3, the highest number that does not exceed 2109 is 256:
2109 = 8(256)+ 61
Finally, 61 = 3(16) + 13. So we have
\begin{aligned} 14397 & =3(4096)+8(256)+3(16)+13 \\ & =3\left(16^3\right)+8\left(16^2\right)+3\left(16^1\right)+13\left(16^0\right) \end{aligned}From Table 1.2 we see that 13_{10} is D in hexadecimal, so we have
14 397_{10} = 3830_{16}Table 1.2
Hexadecimal numbers.
\begin{array}{cc|cc} \hline \text { Decimal } & \text { Hexadecimal } & \text { Decimal } & \text { Hexadecimal } \\ \hline 0 & 0 & 8 & 8 \\ 1 & 1 & 9 & 9 \\ 2 & 2 & 10 & \mathrm{~A} \\ 3 & 3 & 11 & \mathrm{~B} \\ 4 & 4 & 12 & \mathrm{C} \\ 5 & 5 & 13 & \mathrm{D} \\ 6 & 6 & 14 & \mathrm{E} \\ 7 & 7 & 15 & \mathrm{~F} \\ \hline \end{array}