Question 20.12.5: Find the equation of the x line parallel to the y-axis and d......
Find the equation of the x line parallel to the y -axis and drawn through the point of intersection of the lines x-7 y+5=0 and 3 x+y-7=0 .
Step-by-Step
The equation of any line through the point of intersection of the given lines is of the form
\begin{aligned}& (x-7 y+5)+k(3 x+y-7)=0 \\ \\\Rightarrow \quad & (1+3 k) x+(k-7) y+(5-7 k)=0\qquad …(i)\end{aligned}If the line is parallel to y -axis then coefficient of y should be 0 , i.e., k-7=0 , which gives k=7 .
Substituting k=7 in (i), we get: 22 x-44=0\\ \therefore \quad x-2=0 , which is the required equation.
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