Find the point to which the origin be shifted after a translation, so that the equation x^{2}+y^{2}-4 x-8 y+3=0 will have no first degree terms.
Let the origin O be shifted to a point O^{\prime}(h, k) .
Let the new coordinates of P(x, y) be P\left(x^{\prime}, y^{\prime}\right) .
Then, x^{\prime}=x-h \Rightarrow x=x^{\prime}+h .
And, y^{\prime}=y-k \Rightarrow y=y^{\prime}+k .
So, the new equation becomes:
Since we are required to get an equation free from first degree terms, so we have:
\begin{aligned}& (2 h-4=0 \text { and } 2 k-8=0)\\ \\\Rightarrow & (2 h=4 \text { and } 2 k=8) \Rightarrow (h=2 \text { and } k=4) .\end{aligned}Hence, the origin O should be shifted to the point O^{\prime}(2,4) .