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Question 20.11.5: Find the point to which the origin be shifted after a transl......

Find the point to which the origin be shifted after a translation, so that the equation x^{2}+y^{2}-4 x-8 y+3=0 will have no first degree terms.

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Let the origin O be shifted to a point O^{\prime}(h, k) .

Let the new coordinates of P(x, y) be P\left(x^{\prime}, y^{\prime}\right) .

Then, x^{\prime}=x-h  \Rightarrow   x=x^{\prime}+h .

And, y^{\prime}=y-k  \Rightarrow   y=y^{\prime}+k .

So, the new equation becomes:

\begin{aligned}& \left(x^{\prime}+h\right)^{2}+\left(y^{\prime}+k\right)^{2}-4\left(x^{\prime}+h\right)-8\left(y^{\prime}+k\right)+3=0 \\  \\\Rightarrow &   \left(x^{\prime 2}+h^{2}+2 x^{\prime} h\right)+\left(y^{\prime 2}+k^{2}+2 y^{\prime} k\right)-4\left(x^{\prime}+h\right)-8\left(y^{\prime}+k\right)+3=0\\  \\\Rightarrow &   x^{\prime 2}+y^{\prime 2}+(2 h-4) x^{\prime}+(2 k-8) y^{\prime}+\left(h^{2}+k^{2}-4 h-8 k+3\right)=0 .\end{aligned}

Since we are required to get an equation free from first degree terms, so we have:

\begin{aligned}& (2 h-4=0 \text { and } 2 k-8=0)\\  \\\Rightarrow &   (2 h=4 \text {  and  } 2 k=8)  \Rightarrow   (h=2 \text {  and  } k=4) .\end{aligned}

Hence, the origin O should be shifted to the point O^{\prime}(2,4) .

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